Optimal. Leaf size=187 \[ \frac{4 e^3}{a^2 d \sqrt{e \sin (c+d x)}}-\frac{2 e^3 \cos ^3(c+d x)}{a^2 d \sqrt{e \sin (c+d x)}}-\frac{2 e^3 \cos (c+d x)}{a^2 d \sqrt{e \sin (c+d x)}}-\frac{44 e^2 E\left (\left .\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )\right |2\right ) \sqrt{e \sin (c+d x)}}{5 a^2 d \sqrt{\sin (c+d x)}}+\frac{4 e (e \sin (c+d x))^{3/2}}{3 a^2 d}-\frac{12 e \cos (c+d x) (e \sin (c+d x))^{3/2}}{5 a^2 d} \]
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Rubi [A] time = 0.596152, antiderivative size = 187, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 9, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.36, Rules used = {3872, 2875, 2873, 2567, 2640, 2639, 2564, 14, 2569} \[ \frac{4 e^3}{a^2 d \sqrt{e \sin (c+d x)}}-\frac{2 e^3 \cos ^3(c+d x)}{a^2 d \sqrt{e \sin (c+d x)}}-\frac{2 e^3 \cos (c+d x)}{a^2 d \sqrt{e \sin (c+d x)}}-\frac{44 e^2 E\left (\left .\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )\right |2\right ) \sqrt{e \sin (c+d x)}}{5 a^2 d \sqrt{\sin (c+d x)}}+\frac{4 e (e \sin (c+d x))^{3/2}}{3 a^2 d}-\frac{12 e \cos (c+d x) (e \sin (c+d x))^{3/2}}{5 a^2 d} \]
Antiderivative was successfully verified.
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Rule 3872
Rule 2875
Rule 2873
Rule 2567
Rule 2640
Rule 2639
Rule 2564
Rule 14
Rule 2569
Rubi steps
\begin{align*} \int \frac{(e \sin (c+d x))^{5/2}}{(a+a \sec (c+d x))^2} \, dx &=\int \frac{\cos ^2(c+d x) (e \sin (c+d x))^{5/2}}{(-a-a \cos (c+d x))^2} \, dx\\ &=\frac{e^4 \int \frac{\cos ^2(c+d x) (-a+a \cos (c+d x))^2}{(e \sin (c+d x))^{3/2}} \, dx}{a^4}\\ &=\frac{e^4 \int \left (\frac{a^2 \cos ^2(c+d x)}{(e \sin (c+d x))^{3/2}}-\frac{2 a^2 \cos ^3(c+d x)}{(e \sin (c+d x))^{3/2}}+\frac{a^2 \cos ^4(c+d x)}{(e \sin (c+d x))^{3/2}}\right ) \, dx}{a^4}\\ &=\frac{e^4 \int \frac{\cos ^2(c+d x)}{(e \sin (c+d x))^{3/2}} \, dx}{a^2}+\frac{e^4 \int \frac{\cos ^4(c+d x)}{(e \sin (c+d x))^{3/2}} \, dx}{a^2}-\frac{\left (2 e^4\right ) \int \frac{\cos ^3(c+d x)}{(e \sin (c+d x))^{3/2}} \, dx}{a^2}\\ &=-\frac{2 e^3 \cos (c+d x)}{a^2 d \sqrt{e \sin (c+d x)}}-\frac{2 e^3 \cos ^3(c+d x)}{a^2 d \sqrt{e \sin (c+d x)}}-\frac{\left (2 e^2\right ) \int \sqrt{e \sin (c+d x)} \, dx}{a^2}-\frac{\left (6 e^2\right ) \int \cos ^2(c+d x) \sqrt{e \sin (c+d x)} \, dx}{a^2}-\frac{\left (2 e^3\right ) \operatorname{Subst}\left (\int \frac{1-\frac{x^2}{e^2}}{x^{3/2}} \, dx,x,e \sin (c+d x)\right )}{a^2 d}\\ &=-\frac{2 e^3 \cos (c+d x)}{a^2 d \sqrt{e \sin (c+d x)}}-\frac{2 e^3 \cos ^3(c+d x)}{a^2 d \sqrt{e \sin (c+d x)}}-\frac{12 e \cos (c+d x) (e \sin (c+d x))^{3/2}}{5 a^2 d}-\frac{\left (12 e^2\right ) \int \sqrt{e \sin (c+d x)} \, dx}{5 a^2}-\frac{\left (2 e^3\right ) \operatorname{Subst}\left (\int \left (\frac{1}{x^{3/2}}-\frac{\sqrt{x}}{e^2}\right ) \, dx,x,e \sin (c+d x)\right )}{a^2 d}-\frac{\left (2 e^2 \sqrt{e \sin (c+d x)}\right ) \int \sqrt{\sin (c+d x)} \, dx}{a^2 \sqrt{\sin (c+d x)}}\\ &=\frac{4 e^3}{a^2 d \sqrt{e \sin (c+d x)}}-\frac{2 e^3 \cos (c+d x)}{a^2 d \sqrt{e \sin (c+d x)}}-\frac{2 e^3 \cos ^3(c+d x)}{a^2 d \sqrt{e \sin (c+d x)}}-\frac{4 e^2 E\left (\left .\frac{1}{2} \left (c-\frac{\pi }{2}+d x\right )\right |2\right ) \sqrt{e \sin (c+d x)}}{a^2 d \sqrt{\sin (c+d x)}}+\frac{4 e (e \sin (c+d x))^{3/2}}{3 a^2 d}-\frac{12 e \cos (c+d x) (e \sin (c+d x))^{3/2}}{5 a^2 d}-\frac{\left (12 e^2 \sqrt{e \sin (c+d x)}\right ) \int \sqrt{\sin (c+d x)} \, dx}{5 a^2 \sqrt{\sin (c+d x)}}\\ &=\frac{4 e^3}{a^2 d \sqrt{e \sin (c+d x)}}-\frac{2 e^3 \cos (c+d x)}{a^2 d \sqrt{e \sin (c+d x)}}-\frac{2 e^3 \cos ^3(c+d x)}{a^2 d \sqrt{e \sin (c+d x)}}-\frac{44 e^2 E\left (\left .\frac{1}{2} \left (c-\frac{\pi }{2}+d x\right )\right |2\right ) \sqrt{e \sin (c+d x)}}{5 a^2 d \sqrt{\sin (c+d x)}}+\frac{4 e (e \sin (c+d x))^{3/2}}{3 a^2 d}-\frac{12 e \cos (c+d x) (e \sin (c+d x))^{3/2}}{5 a^2 d}\\ \end{align*}
Mathematica [C] time = 3.08798, size = 249, normalized size = 1.33 \[ \frac{4 \cos ^4\left (\frac{1}{2} (c+d x)\right ) \sec ^2(c+d x) (e \sin (c+d x))^{5/2} \left (\csc ^2(c+d x) \left (20 \sin (c) \cos (d x)-3 \sin (2 c) \cos (2 d x)+20 \cos (c) \sin (d x)-3 \cos (2 c) \sin (2 d x)+\sec \left (\frac{c}{2}\right ) \left (60 \sin \left (\frac{d x}{2}\right ) \sec \left (\frac{1}{2} (c+d x)\right )-36 \sin \left (\frac{3 c}{2}\right ) \sec (c)\right )-96 \tan \left (\frac{c}{2}\right ) \sec (c)\right )+\frac{352 i e^{2 i (2 c+d x)} \left (3 \text{Hypergeometric2F1}\left (-\frac{1}{4},\frac{1}{2},\frac{3}{4},e^{2 i (c+d x)}\right )+e^{2 i d x} \text{Hypergeometric2F1}\left (\frac{1}{2},\frac{3}{4},\frac{7}{4},e^{2 i (c+d x)}\right )\right )}{\left (1+e^{2 i c}\right ) \left (1-e^{2 i (c+d x)}\right )^{5/2}}\right )}{15 a^2 d (\sec (c+d x)+1)^2} \]
Antiderivative was successfully verified.
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Maple [A] time = 1.766, size = 173, normalized size = 0.9 \begin{align*}{\frac{2\,{e}^{3}}{15\,{a}^{2}\cos \left ( dx+c \right ) d} \left ( 66\,\sqrt{-\sin \left ( dx+c \right ) +1}\sqrt{2+2\,\sin \left ( dx+c \right ) }\sqrt{\sin \left ( dx+c \right ) }{\it EllipticE} \left ( \sqrt{-\sin \left ( dx+c \right ) +1},1/2\,\sqrt{2} \right ) -33\,\sqrt{-\sin \left ( dx+c \right ) +1}\sqrt{2+2\,\sin \left ( dx+c \right ) }\sqrt{\sin \left ( dx+c \right ) }{\it EllipticF} \left ( \sqrt{-\sin \left ( dx+c \right ) +1},1/2\,\sqrt{2} \right ) +3\, \left ( \cos \left ( dx+c \right ) \right ) ^{4}-10\, \left ( \cos \left ( dx+c \right ) \right ) ^{3}-33\, \left ( \cos \left ( dx+c \right ) \right ) ^{2}+40\,\cos \left ( dx+c \right ) \right ){\frac{1}{\sqrt{e\sin \left ( dx+c \right ) }}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{{\left (e^{2} \cos \left (d x + c\right )^{2} - e^{2}\right )} \sqrt{e \sin \left (d x + c\right )}}{a^{2} \sec \left (d x + c\right )^{2} + 2 \, a^{2} \sec \left (d x + c\right ) + a^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (e \sin \left (d x + c\right )\right )^{\frac{5}{2}}}{{\left (a \sec \left (d x + c\right ) + a\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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